TABLE I
Initial and Boundary Conditions for Modeling Case Studies
| Case #1 Diffusion | Case #2 Effusion | Case #3 Effusion-in Small Total Pressure Differential | Case #4 Effusion-in Large Total Pressure Differential | |
|---|---|---|---|---|
| Effusion-out | Effusion-in | |||
no mass/volumetric flowat any time t, | Pe0(t ≥ 0) = 10 mmHg = 1333.22 pascal, vacuum pressure outside of vial | Pe0(t ≥ 0) = 760 mmHg = 101325.02 pascal, air pressure outside of vial | Pe0(t ≥ 0) = 1 atm = 101325 pascal,air pressure outside of vial | Pe0(t ≥ 0) = 1 atm = 101325 pascal, air pressure outside of vial |
| Pe(t = 0) = 760 mmHg = 101325.02 pascal, air pressure in vial | Pe(t = 0) = 10 mmHg= 1333.22 pascal,air pressure in vial | Pe(t = 0) = 900 mbar = 90000 pascals of nitrogen, nitrogen pressure inside of vial | Pe(t = 0) = 300 mbar = 30000 pascals of nitrogen, nitrogen pressure inside of vial | |
| Pd(t = 0, x = 0) = 20.9%(atm)= 21176.93 pascal, partial oxygen pressure outside of vial at t = 0 | Pd(t = 0, x = 0) =10 mmHg = 1333.22 pascal,vacuum pressure outside of vial at t = 0 | Pd(t = 0, x = 0) = 760 mmHg = 101325.02 pascal, air pressure outside of vial at t =0 | Pd(t = 0, x = 0) = 20.9% (atm) = 21176.93 pascal, partial oxygen pressure outside of vial t =0 | Pd(t = 0, x = 0) = 20.9% (atm) = 21176.93 pascal, partial oxygen pressure outside of vial t = 0 |
| Pd(t = 0, 0 < x ≤ L) = 0.0%(atm) = 0.0 pascal, partial oxygen pressure in vial & leak path at t = 0 | Pd(t = 0, 0 < x≤ L) = 760 mmHg = 101325.02 pascal, air pressure in vial & leak path t = 0 | Pd(t = 0, 0<x ≤ L) = 10 mmHg = 1333.22 pascalair pressure in vial and leak path t =0 | Pd(t = 0, 0 < x ≤ L) = 0.0%(atm) = 0.0 pascal, partial oxygen pressurein vial & leak path t =0 | Pd(t = 0, 0 < x ≤ L) = 0.0% (atm) = 0.0 pascal, partial oxygen pressurein vial & leak path at t = 0 |
| Pd(t = t, x = 0) = 20.9% (atm) = 21176.93 pascal, partial oxygen pressure outside of vial at t = t | Pd(t = t, x = 0) = 10 mmHg = 1333.22 pascal, vacuum pressure outside of vial t = t | Pd(t = t, x = 0) =760 mmHg = 101325.02 pascal, air pressure outside of vial t = t | Pd(t = t, x = 0) = 20.9% (atm) = 21176.93 pascal, partial oxygen pressure outside of vial t = t | Pd(t = t, x = 0) = 20.9% (atm) = 21176.93 pascal, partial oxygen pressure outside of vial t = t |
 partial oxygen pressure in vial at t = t |  air pressure in vial at t = t |  air pressure in vial at t = t |  patial oxygen pressure in vial at t = t |  partial oxygen pressure in vial at t = t |